新人求问= =

要求写一个出现成这样的程序
Enter some text: Hello, World!
h 1
e 1
l 3
o 2
w 1
r 1
d 1
然后我现在写成这样：
a = input('Enter some text: ')
b = list(set(a))
for item in b:
print(item, a.count(item))
得出这样：
Enter some text: Hello, World!
o 2
l 3
, 1
d 1
! 1
H 1
e 1
r 1
W 1
1
要用.isalpha() 来去掉空格和符号，可是我不知道加在哪里
老是变成这样：
Traceback (most recent call last):
File "program.py", line 3, in <module>
for item in b.isalpha():
AttributeError: 'list' object has no attribute 'isalpha'
还有据说要用if语句，可是我不知道怎么用在这儿
新的不能再新的新人，没学多少，求大神用简单地方法教我一下吧！
谢谢啦！

哦对了，得出的结果顺序还要和题目一样= =
大神快出现吧！

强行用一下isalpha()也是可以的.

a = input('Enter some text: ').lower()
b = list(set(a))
for item in b:
c = item
if c.isalpha():
print(c, a.count(c))
解出来了！！是不是我的比较简单！！

python Palindrome
就是正过来反过来一样
Your task here is to write a program to read in two non-negative integers, begin and end, and print out all of the palindromes which occur between begin and end (inclusive). For example:
Enter begin: 950
Enter end: 1200
959 is a palindrome
969 is a palindrome
979 is a palindrome
989 is a palindrome
999 is a palindrome
1001 is a palindrome
1111 is a palindrome
There are 7 palindrome(s) between 950 and 1200
Here is another example:
Enter begin: 50
Enter end: 70
55 is a palindrome
66 is a palindrome
There are 2 palindrome(s) between 50 and 70
然后给出的已有程序是：
begin = int(input('Enter begin: '))
end = int(input('Enter end: '))
palindromes = 0
# Add your code here. You will want to start with a "for x in range" style loop.
print('There are', palindromes, 'palindrome(s) between', begin, 'and', end)
大神们快来赐教！